This works similary for "with_people" and for "with_keywords" - in both case you must use the numerical ID of the person/keyword. This is true even though the API reference for Discover->Movie, for example, states that these values are strings. I tried with_keywords using both words (such as "Batman") and out of range numbers (such as "2"), but the first page of roughly 832,000 results were returned. Only when using a valid keyword ID (such as 4344 for "musical") will this work.
codenametyler 的回复
于 2019 年 02 月 08 日 6:57上午
correct me if am wrong, we can use the filters in movie discovery to achieve it. https://developers.themoviedb.org/3/discover/movie-discover
Travis Bell 的回复
于 2019 年 02 月 08 日 3:57下午
Hi @codenametyler,
Yes, you can use /discover. You'll want to look at using the
with_people
filter. Looking at Brad Pitt as an example:codenametyler 的回复
于 2019 年 02 月 11 日 12:52上午
Hello @travisbell ,
that exactly what i did, with an autocomplete to get the peopleID. XD
Cheers
msheliga1 的回复
于 2023 年 12 月 22 日 4:25下午
This works similary for "with_people" and for "with_keywords" - in both case you must use the numerical ID of the person/keyword. This is true even though the API reference for Discover->Movie, for example, states that these values are strings. I tried with_keywords using both words (such as "Batman") and out of range numbers (such as "2"), but the first page of roughly 832,000 results were returned. Only when using a valid keyword ID (such as 4344 for "musical") will this work.
Travis Bell 的回复
于 2023 年 12 月 22 日 4:48下午
The docs state strings because values like "9663|9748" and "9663,9748" are valid in order to issue an
OR
orAND
query.