Getting information from tmdb fail

Axuda de The Movie Database

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Publicado por Wong
STAFFMOD
o 19 de febreiro do 2016 ás 12:51PM

Hi, i have some problem with my script to get tmdb movie keywords.

This is my scripts that i use

if(key == "keywords"){
            var keyw = "";
            $.each( tmdbdata.keywords, function( i, item ) {
                keyw += "" + item.name + ", ";
            });
            $('input[name="keywords"]').val( keyw );
}

The result is: undefined, . whats wrong?

I use same metod to get backdrops with this code

if(key == "images"){
            var imgt = "";
            $.each( tmdbdata.images.backdrops, function( i, item ) {
                imgt += "https://image.tmdb.org/t/p/w300" + item.file_path + "\n";  
            });
            $('textarea[name="imagenes"]').val( imgt );
}

it's work properly

anyone can help?

3 respostas (na páxina 1 de 1)

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Resposta de Travis Bell

STAFFMOD

no 19 de febreiro do 2016 ás 6:23PM

Hi WongKentir,

I think I can assume you're using append_to_response so if that's case, you're probably looking for:

$.each( tmdbdata.keywords.keywords, function( i, item ) {

I think. If not, then I'll need to see an example request (full URL) you're making.

Resposta de Wong

STAFFMOD

no 20 de febreiro do 2016 ás 3:37AM

Wow, this great. thanks travis, Love your tips. it's work.

Short, sharp and to the point.

I’m no PHP/Script expert but you guys make learning so much easier. :)

Are you familiar with wordpress?

In other case, I do the same result with another code.

$.getJSON( url + input + "/keywords?" + apikey, function(tmdbdata) {
    $.each(tmdbdata, function(key, val) {
        if(key == "keywords"){
            var valKywd = "";
            $.each( tmdbdata.keywords, function( i, item ) {
            valKywd += "" + item.name + ", "; //
        });
            $('#new-tag-<?php echo get_option("country"); ?>').val( valKywd );
        }
    });
});

It works pretty good, but i don't want custom tax "country". i want default tax of tags, to auto fill up the taxonomy.

i already tried with: tag, tags, post-tags, but not work. Have any idea to solve this case?

Resposta de Wong

STAFFMOD

no 21 de febreiro do 2016 ás 11:57PM

SOLVED, thanks :)

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