By using the callback param, you're actually calling JSONP and what this is doing is wrapping your JSON in a JavaScript function. Regular JSON is returned by not specifying the callback param. I'm not sure which you're expecting, but it is working as designed (regular JSON):
Travis Bell 的回复
于 2015 年 09 月 05 日 12:32下午
Hi mikhailtpm,
By using the
callback
param, you're actually calling JSONP and what this is doing is wrapping your JSON in a JavaScript function. Regular JSON is returned by not specifying thecallback
param. I'm not sure which you're expecting, but it is working as designed (regular JSON):Vs. JSONP (callback=test):
Cheers.