Yes, that is not a working API call. Are you simply trying to call the images method on movie id 1948?

https://api.themoviedb.org/3/movie/1948/images?api_key=###

Would be what you're after.

I want to get the movie through a backdrop_path string I try to put in python this image into a canvas_image tkinter element

I'm not following. Could you elaborate?

Once you have made a request for the images, you can pull out the file_path element from within the results. With that in hand, follow the instructions located in the configuration method to build a fully qualified URL.

My first Request is from these api: "https://api.themoviedb.org/3/search/movie?my_key&query=" There´s a backdrop_path': u'/4406KIS6HsScPFs66xOVaeQK3Nj.jpg within.

I´m going to use the - ---backdrop_path----- value to build a string that leads to the picture url. When I got that picture I want to put it in the python canvas image object. There´s the theory so far, I´m very new in python and got to work it out.

while zaehler > 1:
z += 1 zaehler -= 1 label["label%d" % z] = Label(text = "Titel") entry["entry%d" % z] = Entry() canvas = Canvas(width=100, height=100) canvas.create_text(70,30,text = "test") #canvas.create_image(80,30,image = self.image_string + THE STRING I WANT TO USE) canvas.pack()

Ah, I have no idea about Python or Canvas. Sorry.

Hello Travisbell,

I mean I need the full path to the images itself to request the image I think that´s my Question

Did you read through the configuration method like I mentioned? It explains how you generate a fully qualified URL.

Now I see, thank you! The word configuration was confusing me, because in php configuration means always system or application data configurations

I have the same problem but the page that was the solution to Northstar's problem has depreciated. My problem is that I want a direct link to the poster from either a query or an id both are fine but i am not able to get that. My question is what to do with the file path that I receive what should I put in front of the file path so that I get a direct image link. The code is in python by the way

{"status_code":7,"status_message":"Invalid API key: You must be granted a valid key.","success":false} I am getting this error when i use this link: https://api.themoviedb.org/3/search/movie?query=ready+player+one&page=1&language=en-US&api_key=api_key_here/poster_path-here.jpg

i already have a program running on this API so i know the API is running

@panthermail said:

https://api.themoviedb.org/3/search/movie?query=ready+player+one&page=1&language=en-US&api_key=api_key_here/poster_path-here.jpg

That's not a valid request. You're appending the poster path to your API key.

https://api.themoviedb.org/3/search/movie?query=ready+player+one&page=1&language=en-US&api_key=api_key_here

Is a valid search query.

If you want to get images, read the docs for the details: https://developer.themoviedb.org/docs/image-basics

Thank you soooo much this is exactly what i was looking for and i had no idea tmdb had any other documentation than the tmdb api reference